Thread

Hello fran-quero,

Thanks so much for the compliment, I really appreciate it.

There is a select function in $ajax->select() that allows to deal with dropdowns/select elements. To fill ‘select’ elements. You just supply an array. Please see these samples:

http://cjax.sourceforge.net/examples/propagate_dropdown.php

http://cjax.sourceforge.net/examples/propagate_dropdown.php

This is how it would propagate data into select elements:

//Sample1
$data = array('key' => 'value', 'key2' => 'value2');

$ajax->select('zip',$data);  


//Sample2   will show value2 as selected default
$ajax->select('select1',$data, 'key2');

On third parameter, you specify which item should be the selected default.

Hope this helps, and do let me know if you run into any issues.

May I ask for a favor?, can you please post your review here: https://sourceforge.net/projects/cjax/reviews/
I will appreciate it even more, thanks!.

Update:
There are usually more than one way to accomplish things with Cjax, glad you found a solution.

Ajaxboy

Thank you for the select info, I’ll check it out. I have to go deeper in the documentation.

Just made my review in Sourforge!

Now I have new question. With this code I show a modal if an identification id exists in a database table:

$ajax->Exec('id', $ajax->overlay(base_url().'ajax/newuser/checkid/|id|'), 'blur');

It works, but I’d like it to JUST show the modal if the id is found. When an id is not found cAjax shows an empty modal. Is that possible?

Not too sure without knowing the full scope but generally speaking, when you pull the data from the database, you might want to add a check, for example:

if ($id)  {
     $ajax->Exec('id', $ajax->overlay(base_url().'ajax/newuser/checkid/|id|'), 'blur'); 

}

It’s an alert based on the value introduced by the user, so I can’t use if(), because, I search the id in the database once the input field for id loses focus. And this way, although the controller response is empty, $ajax->overlay() shows an empty modal.

I’ll look for alternative ways.

Thank you for your answer.

Hi Ajaxboy,

Could you help me please?

How do I execute a synchronous call using cjax?

Hello. Give me a hand with this, please.

I’m trying to use $this->input->post in my ajax controller (application/response/controller), but I always get undefined.

$ajax->alert($form_fields['name']); //print value successfully
$ajax->alert($this->input->post('a[name]')); //print undefined
$ajax->alert($this->input->post($form_fields['name'])); //print undefined

Can’t I use input->post in the ajax controller?

are you submitting a form with cjax?, if so you should be able to get the values in the $_POST variable or $this->input->post,  are you monitoring the ajax requests? if so make sure it’s using post.

That is what I’m doing:

1) /application/controllers/customers.php

public function new_customer()
{
     $this->load->helper('form');
     
      $this->data['nombre'] = array(
                                    'name' => 'a[name]',
                                    'id'   => 'name',
                                    'type' => 'text',
                            );
                            $this->data['lastname'] = array(
                                    'name' => 'a[lastname]',
                                    'id'   => 'lastname',
                                    'type' => 'text',
                            );

  $this->load->file(FCPATH.'ajaxfw.php');
  $ajax = ajax();
  $ajax->sendButton = $ajax->form(base_url().'ajax/newcustomer/validateNewCustomer');
  load_view('v_newCustomer', $this->data);

2) /views/v_newCustomer.php
(script tag bad spelled to avoid it being removed)

<scrip defer='defer' id='cjax_lib' type='text/javascript' src='<?php echo base_url();?>/cjax/core/js/cjax-5.5.min.js'></scrip>

<?php echo form_open("");?>


                name: 
                <?php echo form_input($name);?>
                
                    
                      Last name:
                      <?php echo form_input($lastname);?>
                

<?php echo form_submit('submit', 'New customer','id="sendButton"');?>
      
<?php echo form_close();?>

3) /response/newcustomer/validateNewCustomer.php

$ajax = ajax();
$ajax->alert($form_fields['name']); //print value successfully
$ajax->alert($this->input->post('a[name]')); //print undefined
$ajax->alert($this->input->post($form_fields['name'])); //print undefined

Hi Ajaxboy,

and sorry if I repeat the question but I need to do a synchro call using the framework. How can I do it without using pure ajax or Jquery but using only Cjax?

Thank you.

Is it possible to bind elements generated dinamically, like jQuery .live() or .on() methods?

I have created an cAjax exec call to an element, that works when the element is in the main view, but doesn’t when it’s loaded by other cAjax call.

$ajax->Exec('zip', $ajax->call(base_url().'ajax/newcustomer/locations/|zip|','location'), 'blur');

As long the element exist you should be able to attach any event. Otherwise you might need to wait for some sort of trigger until the element is created.

By the way, are you using firebug? or chrome ajax debugger? One of these is essential to be able to debug raw requests which give you more direct information while debugging and fixing stuff

Am I missing something simple here?

I’ve installed AJAXFW CI 5.4, on Codeigniter version 2.1.4. When I go to run the initial test following the instructions on this page, I get a blank page with no message or error. The network inspector shows that ajax.php?test/test is being fetched successfully.

I’ve tried this setup on both my local Codeigniter install as well as on a live remote server, both times with the same result. Any help getting this up and running would be greatly appreciated!

Make sure you meet the minimum requirements:

https://github.com/ajaxboy/cjax

Ps, the latest is Cjax 5.5

Hey, thanks for the speedy reply!

I’ve upgraded to 5.5, but still no luck with the initial test. Just an empty page. I’m running locally on MAMP using a virtual host, so the URL looks like: dev.myproject:8888/ajax.php?test/test

MAMP is running PHP 5.3.6

I’m using MOD Rewrite to remove the index.php segment but I haven’t implemented the ajax rewrite rule that came with the project folder.

My directory structure looks like this:

application/
  - response/
      -sample.php
      -test.php
  - controllers/
      - AjaxController.php
  - views/
      test.php
      test2.php
ajax.php
ajaxfw.php
cjax/
examples/
index.php
system/