Thread

I am having issues wrapping my head around an idea I have for a project.

Here is the idea:

I want to split up entries into rows of three and then have some extra code placed after each row. Then I want the process to continue until all the entries have been listed.

Example:

<div class=“row”>
<div>Entry One</div>
<div>Entry Two</div>
<div>Entry Three</div>
</div>

<div>(extra content)</div>

<div class=“row”>
<div>Entry Four</div>
<div>Entry Five</div>
<div>Entry Six</div>
</div>

<div>(extra content)</div>

...and so on.

This is probably a very simply process, but I can’t seemed to figure it out. Any help would be greatly appreciated.

EE 2.2.1
Build 20110705

Adam Wiggall recently posted this solution to the same problem on Google+.  PHP would need to be enabled on your template in order for it to work, as it uses PHP…

<?php $counter = 0; ?>

{exp:entries tags}

<?php $counter += 1; ?>
<?php if ( $counter == 1 || $counter % 3 == 1 ): ?>
   <div class="row">
<?php endif; ?>

      <div>Entry {count}</div>

<?php if ( $counter % 3 == 0 || $counter == '{total_results}' ): ?>
   </div>
   <div>(extra content)</div>
<?php endif; ?>
{/exp:entries tags}

Shinetime,

Another option is to use the Switch parameter if you are doing this as part of an exp:channel:entries tag.

Generally speaking to do something like what you are talking about you would do this:

{switch='||<div>(extra content)</div>'}

Switch will only throw that tag in after every third entry though.  If you have a situation with 8 entries instead of 9, the last <div>(extra content)</div> wouldn’t show up.  If that case isn’t a problem (in other words, if you know the number of entries shown will always be a multiple of 3), the switch parameter is probably a better / less complicated option.

Nick - Thanks so much man! That is exactly what I was looking for! You have officially put the final touches on a template for me… AND for that I really really thank you.

Marcus, thanks as I can probably use switch in some other instances. This is an every growing channel in which the count won’t always be a multiple of three.

Thanks again for all the help!

Glad you got it sorted out.