Thread

Is it possible to set conditionals in Snippets?

I have a Global Variable set named “google analytics” and have the following conditional in “snp_footer” Snippet:

{if google_analytics}
[removed]
var _gaq = _gaq || [];
...
[removed]
{/if}

When try to load a page it doesn’t add the Google Analytics script.

Hi R Gruyters,

What does {google_analytics} output on its own inside the snippet? Also, if you’re setting the global variable via index.php, that won’t currently work and you’ll need to define it via the Control Panel instead.

{google_analytics} displays the Google code when I call it within a snippet.

{google_analytics} is set in the Global Variable in the Control Panel.

I might be wrong but as global variables are one of the last thing parsed via ExpressionEngine and snippets are quite early on is this perhaps a parse order problem here?

Best wishes,

Mark

EDIT - Actually a daft question here but can you even perform a conditional on a global variable anyway?

Also unless I’m doing something really silly I can’t even get Global Variables to work at all in 2.1.4 :-(

I tried this :

{if global_test == "yes"}
Output this
{/if}

global_test is a global variable set via the templates manager and contains the word yes.

Same here. But you can display it within a snippet and template right? ({global_test})

Yep a global variable can go both in a snippet and a template and shows up fine. I could have sworn you could do conditionals on a user defined global variable but perhaps I’m mistaken there?

Apparently.. 😉

It doesn’t seem to be working.

Hi R Gruyters,

Unless I’m misunderstanding you completely you don’t need a global variable. Just put your GA scripts in a snippet and you can test that snippet in a conditional:

{if my_snippet != ''}
{my_snippet}
{/if}

@Mark, you are correct, a global variable is parsed very late so that’s why the conditional won’t work. A snippet will though.

Does that help?

Cheers

Greg